Since the 1st term is negative, let's factor out -2. SOLUTION TO PROBLEM NUMBER 2 2x3-162(x-2)(x2. Before we factor, we need to find the common factors for the two pairs of terms. Khan Academys mission is to provide a free, world-class education for anyone, anywhere. How To Use The Distributive Property To Factor Out The Greatest Common Factor Khan Academy. Factoring using the difference of squares. Algebraic Factoring By Greatest Common Monomial Factor. = 6 x 2 3 x − 8 x − 4 ( 1 ) = ( 6 x 2 3 x ) ( − 8 x − 4 ) Group terms ( 2 ) = 3 x ( 2 x 1 ) ( − 4 ) ( 2 x 1 ) Factor out GCFs ( 3 ) = 3 x ( 2 x 1 ) − 4 ( 2 x 1 ) Simplify ( 4 ) = 3 x ( 2 x 1 ) − 4 ( 2 x 1 ) Common factor! ( 5 ) = ( 2 x 1 ) ( 3 x − 4 ) Factor out 2 x 1 \begin)x ( B C A D ) x left parenthesis, start color #e07d10, B, end color #e07d10, start color #1fab54, C, end color #1fab54, plus, start color #11accd, A, end color #11accd, start color #aa87ff, D, end color #aa87ff, right parenthesis, x into ( B C ) x ( A D ) x (\goldD B \greenD C)x (\blueD A \purpleC D)x ( B C ) x ( A D ) x left parenthesis, start color #e07d10, B, end color #e07d10, start color #1fab54, C, end color #1fab54, right parenthesis, x, plus, left parenthesis, start color #11accd, A, end color #11accd, start color #aa87ff, D, end color #aa87ff, right parenthesis, x, we will be able to use grouping to factor our expression back into ( A x B ) ( C x D ) (\blueD Ax \goldD B)(\greenD Cx \purpleC D) ( A x B ) ( C x D ) left parenthesis, start color #11accd, A, end color #11accd, x, plus, start color #e07d10, B, end color #e07d10, right parenthesis, left parenthesis, start color #1fab54, C, end color #1fab54, x, plus, start color #aa87ff, D, end color #aa87ff, right parenthesis. Factoring Sum and Difference of Two Cubes: Practice Problems x3 216(x 6)(x2-. Factoring perfect squares: negative common factor (video) Khan AcademySal factors -4t2-12t-9 as -1(2t 3)2.
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